Convert binary to utf 8 python4/23/2024 > b = s.encode('latin-1').decode('unicode_escape'). But in this case the output is simply a string of gibberish, not. Technically, its possible to decode any byte sequence with Latin-1 it wont ever raise an exception. Since you start out with PRxc3x86KVAL as a text string and decode indeed expects a raw byte sequence, you need to convert the text string into a bytes object. MNM decoding this string with Latin-1 doesnt return anything useful. The next issue is the representation in Python. Update Ok I had to look at your byte it was the wrong encoding you need to use ISO-8859-1. But since most OSs predate the Unicode era, they dont have suitable tools to attach the encoding information to files on the hard disk. 'r' indicates a rawstring below, so that the escape sequences are not immediately evaluated in the string-literal assignment. The point of UTF-8 is to be able to encode 21-bit characters (Unicode) as an 8-bit data stream (because thats the only thing all computers in the world can handle). So with latin-1, you can specify the single-byte values in the upper-half of the range directly, instead of the double-bytes that utf-8 would encode for that range. Python assumes latin-1 for the unicode_escape method in the first place because latin-1 is a single-byte coded character-set with code-points that are identical with the abstract Unicode code-points up its maximum of the 255th character. I encoded the final bytestring as utf-8 because that's the most common encoding these days, but depending on what you want to do, you might want to keep it as latin-1 instead.
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